Javascript Disabled Detected

You currently have javascript disabled. Several functions may not work. Please re-enable javascript to access full functionality.

Dzielenie wielomianów, schemat blokowy

Started by Dreamer, 11 Jul 2011 14:42

«
Prev

Next
»

Please log in to reply

791 replies to this topic

#661 Dreamer

Użytkownicy
870 posts

Posted 24 June 2018 - 14:46

A więc koniec.

Edited by Dreamer, 24 June 2018 - 15:34.

0

Back to top

#662 Dreamer

Użytkownicy
870 posts

Posted 24 June 2018 - 14:58

Myślę i myślę i nawet nie zauważyłem jaki jestem zmęczony, a ja się na to teraz sile

Edited by Dreamer, 24 June 2018 - 15:37.

0

Back to top

#663 Dreamer

Użytkownicy
870 posts

Posted 24 June 2018 - 15:16

$(a ^{2}+2ab+b ^{2})(a+b)$
$(c ^{2}+2cb+b ^{2})(c+b)$
$(c ^{2}+2ca+a ^{2})(c+a)$

Edited by Dreamer, 24 June 2018 - 18:45.

0

Back to top

#664 Dreamer

Użytkownicy
870 posts

Posted 24 June 2018 - 16:34

To da się zrobić, tylko po tych nowych smakołykach to zacząłem "fizjonomować" ze zmęczenia, ale zero dyskomfortu, jest świetnie.

0

Back to top

#665 Dreamer

Użytkownicy
870 posts

Posted 24 June 2018 - 18:46

$(b ^{2} \cdot( (a+<img src='https://forum.pcfoster.pl/public/style_emoticons/default/cool.png' class='bbc_emoticon' alt='B)' />+(c+<img src='https://forum.pcfoster.pl/public/style_emoticons/default/cool.png' class='bbc_emoticon' alt='B)' />))+$
$(a ^{2} \cdot( (a+<img src='https://forum.pcfoster.pl/public/style_emoticons/default/cool.png' class='bbc_emoticon' alt='B)' />+(c+a)))+$

0

Back to top

#666 Dreamer

Użytkownicy
870 posts

Posted 24 June 2018 - 18:46

$(c ^{2} \cdot( (c+<img src='https://forum.pcfoster.pl/public/style_emoticons/default/cool.png' class='bbc_emoticon' alt='B)' />+(c+a)))+$

Nie ma to jak odpocząć.

0

Back to top

#667 Dreamer

Użytkownicy
870 posts

Posted 24 June 2018 - 19:07

$(b ^{2} \cdot( (a+c)+b ^{2} ))+$
$(a ^{2} \cdot( (c+<img src='https://forum.pcfoster.pl/public/style_emoticons/default/cool.png' class='bbc_emoticon' alt='B)' />+a ^{2} ))+$
$(c ^{2} \cdot( (a+<img src='https://forum.pcfoster.pl/public/style_emoticons/default/cool.png' class='bbc_emoticon' alt='B)' />+c ^{2} ))+$

0

Back to top

#668 Dreamer

Użytkownicy
870 posts

Posted 24 June 2018 - 19:07

$(b ^{2} \cdot( (a+c)+2b ))+$
$(a ^{2} \cdot( (c+<img src='https://forum.pcfoster.pl/public/style_emoticons/default/cool.png' class='bbc_emoticon' alt='B)' />+2a ))+$
$(c ^{2} \cdot( (a+<img src='https://forum.pcfoster.pl/public/style_emoticons/default/cool.png' class='bbc_emoticon' alt='B)' />+2c ))+$

0

Back to top

#669 Dreamer

Użytkownicy
870 posts

Posted 24 June 2018 - 19:07

$(b ^{2} \cdot( (a+c)+2b ))+$
$(a ^{2} \cdot( (c+<img src='https://forum.pcfoster.pl/public/style_emoticons/default/cool.png' class='bbc_emoticon' alt='B)' />+2a ))+$
$(c ^{2} \cdot( (a+<img src='https://forum.pcfoster.pl/public/style_emoticons/default/cool.png' class='bbc_emoticon' alt='B)' />+2c ))+$
$2(a+<img src='https://forum.pcfoster.pl/public/style_emoticons/default/cool.png' class='bbc_emoticon' alt='B)' /> ^{2} +2(c+<img src='https://forum.pcfoster.pl/public/style_emoticons/default/cool.png' class='bbc_emoticon' alt='B)' /> ^{2} +2(c+a) ^{2}$

0

Back to top

#670 Dreamer

Użytkownicy
870 posts

Posted 24 June 2018 - 19:08

$(b ^{2} \cdot( (a+c)+2b ))+$
$(a ^{2} \cdot( (c+<img src='https://forum.pcfoster.pl/public/style_emoticons/default/cool.png' class='bbc_emoticon' alt='B)' />+2a ))+$
$(c ^{2} \cdot( (a+<img src='https://forum.pcfoster.pl/public/style_emoticons/default/cool.png' class='bbc_emoticon' alt='B)' />+2c ))+$
$2(a+<img src='https://forum.pcfoster.pl/public/style_emoticons/default/cool.png' class='bbc_emoticon' alt='B)' /> ^{2} +2(c+<img src='https://forum.pcfoster.pl/public/style_emoticons/default/cool.png' class='bbc_emoticon' alt='B)' /> ^{2} +2(c+a) ^{2}$

0

Back to top

#671 Dreamer

Użytkownicy
870 posts

Posted 24 June 2018 - 19:08

$2a ^{3}+(a ^{2} +2(c+<img src='https://forum.pcfoster.pl/public/style_emoticons/default/cool.png' class='bbc_emoticon' alt='B)' />)(c+b)$
$2b ^{3}+(b ^{2}+2(a+c))(a+c)$
$2c ^{3}+(c ^{2} +2(a+<img src='https://forum.pcfoster.pl/public/style_emoticons/default/cool.png' class='bbc_emoticon' alt='B)' />)(a+b)$

0

Back to top

#672 Dreamer

Użytkownicy
870 posts

Posted 24 June 2018 - 19:19

$2a ^{3}+a ^{2}(c+<img src='https://forum.pcfoster.pl/public/style_emoticons/default/cool.png' class='bbc_emoticon' alt='B)' /> +2c ^{2} +2b ^{2} +$
$2b ^{3}+b ^{2}(a+c)+2a ^{2} +2c ^{2} +$
$2c ^{3}+c ^{2}(a+<img src='https://forum.pcfoster.pl/public/style_emoticons/default/cool.png' class='bbc_emoticon' alt='B)' /> +2a ^{2} +2b ^{2}$

0

Back to top

#673 Dreamer

Użytkownicy
870 posts

Posted 24 June 2018 - 19:19

$2 \cdot (a ^{3}+b ^{3}+c ^{3})+$
$+a ^{2} \cdot ((c+<img src='https://forum.pcfoster.pl/public/style_emoticons/default/cool.png' class='bbc_emoticon' alt='B)' />+4)$
$+b ^{2} \cdot ((a+c)+4)$
$+c ^{2} \cdot ((a+<img src='https://forum.pcfoster.pl/public/style_emoticons/default/cool.png' class='bbc_emoticon' alt='B)' />+4)$

0

Back to top

#674 Dreamer

Użytkownicy
870 posts

Posted 24 June 2018 - 19:24

$2 \cdot (a ^{3}+b ^{3}+c ^{3})+$
$4 \cdot (a ^{2} +b ^{2}+c ^{2})$

To też się skróci:
$+a ^{2} \cdot (c+b)$
$+b ^{2} \cdot (a+c)$
$+c ^{2} \cdot (a+b)$

0

Back to top

#675 Dreamer

Użytkownicy
870 posts

Posted 24 June 2018 - 19:33

$+a ^{2} \cdot (c+b)$
$+b ^{2} \cdot (a+c)$
$+c ^{2} \cdot (a+b)$

$a ^{2}c+b ^{2}c+ a^{2}b +c ^{2}b+b ^{2}a+c ^{2}a$

$a \cdot (b ^{2}+c ^{2})+$
$b \cdot (a^{2} +c ^{2})+$
$c \cdot (a ^{2}+b ^{2})+$

0

Back to top

#676 Dreamer

Użytkownicy
870 posts

Posted 24 June 2018 - 19:39

$a \cdot (b ^{2}+c ^{2})+$
$b \cdot (a^{2} +c ^{2})+$
$c \cdot (a ^{2}+b ^{2})+$

$a ^{2}(b+c)+b ^{2}(a+c)+ c ^{2}(a+b)$

0

Back to top

#677 Dreamer

Użytkownicy
870 posts

Posted 24 June 2018 - 19:50

Mamy:

$a ^{4} +b ^{4} +c ^{4}+$
$2 \cdot (a ^{3}+b ^{3}+c ^{3})+$
$(a ^{2}+b ^{2}+ c ^{2}) \cdot (((b+c)+(a+c)+(a+<img src='https://forum.pcfoster.pl/public/style_emoticons/default/cool.png' class='bbc_emoticon' alt='B)' />)+4)$

Drugi etap:

$a ^{2} \cdot (permutacja ^{2}(b,c) )$
$+b ^{2} \cdot (permutacja ^{2}(a,c))$
$+c ^{2} \cdot (permutacja ^{2}(a,b)$

0

Back to top

#678 Dreamer

Użytkownicy
870 posts

Posted 24 June 2018 - 19:58

Mamy:

$a ^{4} +b ^{4} +c ^{4}+$
$2 \cdot (a ^{3}+b ^{3}+c ^{3})+$
$(a ^{2}+b ^{2}+ c ^{2}) \cdot( (a+1)(b+c)+4)$

Drugi etap:

$a ^{2} \cdot (permutacja ^{2}(b,c) )$
$+b ^{2} \cdot (permutacja ^{2}(a,c))$
$+c ^{2} \cdot (permutacja ^{2}(a,b)$

$=permutacja ^{4}(a,b,c)$

Na dzisiaj i tak dużo zrobiłem, przerwa.